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I got JEE 7649. Should I pick IIT Chem/Aero or code?

Nayagam P P |6867 Answers |Ask -Follow

Career Counsellor - Answered on Jun 04, 2025

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Question by NGT on Jun 02, 2025Hindi

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As JEE adv results have arrived...I got 7649 CRL and 1632 OBC rank....I am getting Chemical engineering easily in all IITs except Bombay....but in some like Kanpur m getting Aerospace n all too......Just wanted to know towards where should i move forward? (M thinking to do coding and develop skills in coding mainly) My Mains rank was 16820 CRL and 4113 OBC...(Outside Delhi candidate)

Ans: With a JEE Advanced CRL of 7,649 and OBC rank of 1,632, you are eligible for Chemical Engineering at IIT Delhi (2024 OBC closing rank: 2,207), IIT Kanpur (OBC cutoff: 1,944), and IIT Kharagpur (OBC cutoff: 2,100), while Aerospace Engineering at IIT Kanpur (OBC cutoff: 1,944) is feasible. However, Chemical Engineering offers broader flexibility for transitioning into coding roles, with IIT Delhi reporting 90.01% placement rates (2023) and 30–40% of graduates securing IT/analytics roles through electives and internships. In contrast, Aerospace Engineering at IIT Kanpur has a 66.67% placement rate (2024), with limited core-sector opportunities unless supplemented by coding skills. Recommendation: Prioritize Chemical Engineering at IIT Delhi/Kanpur for institutional prestige, interdisciplinary curriculum, and higher placement assurance, leveraging coding clubs, AI/ML electives, and off-campus recruitment for tech roles. If opting for Aerospace, target IIT Kanpur for its research infrastructure but actively pursue coding certifications (Python, Full-Stack) and hackathons. For backups, consider Mathematics & Computing at IIT Gandhinagar (OBC cutoff: 3,500) or ECE at IIT Jodhpur (OBC cutoff: 2,800) to balance core engineering with tech exposure. All the BEST for your Admission & a Prosperous Future!

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